BCD与字符串相互转换

时间：2011-04-15 来源：李帅团

View Code 1 bool BCDtoStr(char *str,unsigned char *BCD,int BCD_length)
2 {
3     if(BCD==0 || BCD_length==0)
4         return false;
5     int i,j;
6     for(i=0,j=0;i<BCD_length;i++,j+=2)
7     {
8         str[j]= (BCD[i]>>4) > 9 ? (BCD[i]>>4)-10+'A' : (BCD[i]>>4)+'0';
9         str[j+1]=(BCD[i] & 0x0F) >9 ? (BCD[i] & 0x0F)-10+'A' : (BCD[i] & 0x0F)+'0';
10     }
11     str[j]='\0';
12     return true;
13 }
14 bool StrtoBCD(char *str,unsigned char *BCD,int *BCD_length)
15 {
16     if(str==0) return false;
17     int tmp=strlen(str);
18     tmp-=tmp%2;
19     if(tmp==0) return false;
20     int i,j;
21     for(i=0;i<tmp;i++)
22     {
23         if(str==0 ||
24             !(str[i]>='0' && str[i]<='9' || str[i]>='a' && str[i]<='f' || str[i]>='A' && str[i]<='F')
25             )
26             return false;
27     }
28
29     for(i=0,j=0;i<tmp/2;i++,j+=2)
30     {
31         str[j]>'9' ?
32             (str[j]>'F' ? BCD[i]=str[j]-'a'+10 : BCD[i]=str[j]-'A'+10)
33             : BCD[i]=str[j]-'0';
34         str[j+1]>'9' ?
35             (str[j+1]>'F' ? BCD[i]=(BCD[i]<<4)+str[j+1]-'a'+10 : BCD[i]=(BCD[i]<<4)+str[j+1]-'A'+10)
36             : BCD[i]=(BCD[i]<<4)+str[j+1]-'0';
37     }
38     if(BCD_length)
39         *BCD_length=tmp/2;
40     return true;
41 }