细节决定成败

时间：2010-09-25 来源：追海逐风

such an easy problem that I didn't AC. WA 4 times.

Problem:

Judge if the (m, d) is a valid date, the year is 2010.

1. 2010 is not a leap year, so February has only 28 days.

2. Negative numbers must be considered.

#include <iostream>

using namespace std;

const int DAYS[] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

int main() {
        int n;
        cin >> n;
        while (n--) {
                int m, d;
                cin >> m >> d;
                cout << ((m < 1 || m > 12 || d < 1 || d > DAYS[m]) ? "No" : "Maybe") << endl;
        }
}

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