java 与 php 发送get请求并获取远程内容...

既然两种语言都玩，就有得对比了，先看JAVA实现，再来看PHP，当然实现的方法有很多种特别是JAVA对于同一种功能的实现绝对比PHP多很多，这点是毫无疑问的！

JAVA实现方法一：

package com.jiucool.www.struts.action; import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.net.MalformedURLException; import java.net.URL; import java.net.URLConnection; public class doget_http_request{ public String doget_http_request(){ StringBuffer readOneLineBuff = new StringBuffer(); String content =""; try { URL url = new URL("http://www.jiucool.com/sendemail.php?key=j0r53nmbbd78x7m1" + "&activatecode=2QyiF0SXXTq8"); URLConnection conn = url.openConnection(); BufferedReader reader = new BufferedReader(new InputStreamReader(conn.getInputStream())); String line = ""; while ((line = reader.readLine()) != null) { readOneLineBuff.append(line); } content = readOneLineBuff.toString(); reader.close(); } catch (MalformedURLException e) { e.printStackTrace(); } catch (IOException e2) { e2.printStackTrace(); } return content; } }

对于PHP的实现，简单得让人要跳楼，看代码：

<?php echo file_get_contents("http://www.jiucool.com/sendemail.php?key=j0r53nmbbd78x7m1&activatecode=2QyiF0SXXTq8");?>

PHP实在太简单了！不过有一点，PHP的弱类型语言让人实在有点不习惯，变量不声明即可使用，太不严谨了！

原文来自我的博客： http://www.jiucool.com/java-php-get-remote-doget-method-content/