python的冒泡排序算法
时间:2011-05-13 来源:狼哥2
def bubblesort(numbers): for j in range(len(numbers)-1,-1,-1): for i in range(j): if numbers[i]>numbers[i+1]: numbers[i],numbers[i+1] = numbers[i+1],numbers[i] print(i,j) print(numbers)
测试代码及输出:
>>> numbers = [1,3,82,77,52,2,100,90] >>> bubblesort(numbers) 0 7 [1, 3, 82, 77, 52, 2, 100, 90] 1 7 [1, 3, 82, 77, 52, 2, 100, 90] 2 7 [1, 3, 77, 82, 52, 2, 100, 90] 3 7 [1, 3, 77, 52, 82, 2, 100, 90] 4 7 [1, 3, 77, 52, 2, 82, 100, 90] 5 7 [1, 3, 77, 52, 2, 82, 100, 90] 6 7 [1, 3, 77, 52, 2, 82, 90, 100] 0 6 [1, 3, 77, 52, 2, 82, 90, 100] 1 6 [1, 3, 77, 52, 2, 82, 90, 100] 2 6 [1, 3, 52, 77, 2, 82, 90, 100] 3 6 [1, 3, 52, 2, 77, 82, 90, 100] 4 6 [1, 3, 52, 2, 77, 82, 90, 100] 5 6 [1, 3, 52, 2, 77, 82, 90, 100] 0 5 [1, 3, 52, 2, 77, 82, 90, 100] 1 5 [1, 3, 52, 2, 77, 82, 90, 100] 2 5 [1, 3, 2, 52, 77, 82, 90, 100] 3 5 [1, 3, 2, 52, 77, 82, 90, 100] 4 5 [1, 3, 2, 52, 77, 82, 90, 100] 0 4 [1, 3, 2, 52, 77, 82, 90, 100] 1 4 [1, 2, 3, 52, 77, 82, 90, 100] 2 4 [1, 2, 3, 52, 77, 82, 90, 100] 3 4 [1, 2, 3, 52, 77, 82, 90, 100] 0 3 [1, 2, 3, 52, 77, 82, 90, 100] 1 3 [1, 2, 3, 52, 77, 82, 90, 100] 2 3 [1, 2, 3, 52, 77, 82, 90, 100] 0 2 [1, 2, 3, 52, 77, 82, 90, 100] 1 2 [1, 2, 3, 52, 77, 82, 90, 100] 0 1 [1, 2, 3, 52, 77, 82, 90, 100]
相关阅读 更多 +