vc++ 6.0 的%u 与 %ul

时间：2011-04-03 来源：laizhd

刚刚在做实验,书本里面有代码如下:

View Code

 1 #include "stdio.h"
 2 
 3 unsigned long lcm(unsigned a,unsigned b);
 4 unsigned long lcm3(unsigned a,unsigned b,unsigned c);
 5 
 6 unsigned long lcm(unsigned a,unsigned b)
 7 {
 8     unsigned long multiple,c=0;
 9 
10     multiple = a* b;
11     while(a%b!=0)
12     {
13         c=a%b;
14         a=b;
15         b=c;
16     }
17 
18     return multiple/b;
19 }
20 
21 unsigned long lcm3(unsigned a,unsigned b,unsigned c)
22 {
23     return lcm(lcm(a,b),c);
24 }
25 
26 
27 int main()
28 {
29     unsigned long x,y,z;
30     printf("please input three number:");
31     scanf("%ul %ul %ul",&x,&y,&z);
32     printf("%ul %ul %ul",x,y,z);
33     printf("the result is %ul",lcm3(x,y,z));
34     return 0;
35 }

基本思路是说想求三个数的公约数,但在vc++ 6.0 里结果却是错的... 后来不断地排除,发现是在vc++ 6.0 里用不了 %ul,必须改成 %u... 修改后的代码如下:

View Code

 1 #include "stdio.h"
 2 
 3 unsigned long lcm(unsigned a,unsigned b);
 4 unsigned long lcm3(unsigned a,unsigned b,unsigned c);
 5 
 6 unsigned long lcm(unsigned a,unsigned b)
 7 {
 8     unsigned long multiple,c=0;
 9 
10     multiple = a* b;
11     while(a%b!=0)
12     {
13         c=a%b;
14         a=b;
15         b=c;
16     }
17 
18     return multiple/b;
19 }
20 
21 unsigned long lcm3(unsigned a,unsigned b,unsigned c)
22 {
23     return lcm(lcm(a,b),c);
24 }
25 
26 
27  int main()
28 {
29     unsigned long x,y,z;
30     printf("please input three number:");
31     scanf("%u %u %u",&x,&y,&z);
32     printf("%u %u %u",x,y,z);
33     printf("the result is %u",lcm3(x,y,z));
34     return 0;
35 }