继续回答问题：1到100以内连续相加和等于100的数输出

#include<iostream> 
using namespace std;
int main()
{
    for(int i = 2; i < 50; ++i)
    {
        int sum = i;
        for(int j = i+1; j < 50; ++j)
        {
            sum += j;
            if(sum == 100)
            {
                for (int k = i; k <= j; ++k)
                {
                    cout << k << " + ";
                }
                cout << "= 100" << endl;
                break;
            }
            if(sum>100)    
                break;    
        }
    }
    cout << "100 = 100 "<< endl;
}