PHP中JSON中文解决
时间：2010-11-20 来源：hegev
json.php
<?php
$json = array ( 0 => array (
'id' => '13',
'name' => '乒乓球',
),
1 => array (
'id' => '17',
'name' => '篮球',
)
);
print_r($json); $code=json_encode($json); echo preg_replace("#\\\u([0-9a-f]+)#ie", "iconv('UCS-2', 'UTF-8', pack('H4', '\\1'))", $code); ?>
json.html <script> $.getJSON("json.php", function(data) { for (var i = 0; i < data.length; i++) { alert(data[i].name); } }); </script>
print_r($json); $code=json_encode($json); echo preg_replace("#\\\u([0-9a-f]+)#ie", "iconv('UCS-2', 'UTF-8', pack('H4', '\\1'))", $code); ?>
json.html <script> $.getJSON("json.php", function(data) { for (var i = 0; i < data.length; i++) { alert(data[i].name); } }); </script>
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