python 函数浅尝 （斐济函数)
时间：2010-11-04 来源：陈力
代码
#include <stdio.h>
代码
int main (int argc, const char * argv[]) {
int numToPrint, i;
double num1, num2, ans;
num1 = 0;
num2 = 1;
printf("How many numbers would you like to print?\t");
scanf("%d", &numToPrint);
printf("1\t%.0f\n2\t%.0lf\n", num1, num2);
for(i = 0; i < (numToPrint - 2); ++i){
ans = (num1 + num2);
printf("%d\t%.0lf\n", i+3, ans);
num1 = num2;
num2 = ans;
}
return 0;
}
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