python 函数浅尝（斐济函数)

时间：2010-11-04 来源：陈力

代码 #include <stdio.h>

int main (int argc, const char * argv[]) {

     int numToPrint, i;
     double num1, num2, ans;

     num1 = 0;
     num2 = 1;

     printf("How many numbers would you like to print?\t");
     scanf("%d", &numToPrint);

     printf("1\t%.0f\n2\t%.0lf\n", num1, num2);

     for(i = 0; i < (numToPrint - 2); ++i){

          ans = (num1 + num2);

          printf("%d\t%.0lf\n", i+3, ans);

          num1 = num2;
          num2 = ans;
     }


    return 0;
}

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