python学习 网络编程(三) nntp连接...

NNTP连接主要是用在新闻组的消息上面，下面的代码演示了NNTP连接的建立，不过显然下面的那个新闻组客户端程序是不能用的。

#!/usr/bin/env python #新闻组客户端程序 import nntplib import socket HOST = 'your.nntp.server' GRNM = 'comp.lang.python' USERNAME = 'Killua' PASSWORD = '123456' def NNTPClient(): try: n = nntplib.NNTP(HOST) except socket.gaierror, e: print 'ERROR: cannot connect host "%s"' % HOST print '("%s")' % eval(str(e))[1] return except nntplib.NNTPPermanentError, e: print 'ERROR: access denied on "%s"' % HOST print '("%s")' % str(e) return print '>> Connected to host "%s"' % HOST try: rsp, ct, fst, lst, grp = n.group(GRNM) except nntplib.NNTPTemporaryError, e: print 'ERROR: cannot load group "%s"' % GRNM print '("%s")' % str(e) print 'Server may require authentication' print 'Uncomment/Edit login lne above' n.quit() return except nntplib.NNTPTemporaryError, e: print 'ERROR: group "%s" unavailable' % GRNM print '("%s")' % str(e) n.quit() return print '>> Found newgroup "%s"' % GRNM rng = '%s-%s' % (lst,lst) rsp, frm = n.xhdr('from', rng) rsp, sub = n.xhdr('subjec', rng) rsp, dat = n.xhdr('date', rng) print ''' Found last article(#%s): From: %s Subject: %s Date: %s ''' (lst, frm[0][1], sub[0][1], dat[0][1]) def displayFirst20(data): 'Display First 20 lines' count = 0 lines = (line.rstrip() for line in data) lastBlank = True for line in lines: if line: lower = line.lower() if (lower.startswith('>') and \ not lower.startswith('>>>')) or \ lower.startswith('|') or \ lower.startswith('in article') or \ lower.endswith('writes:') or \ lower.endswith('wrote:'): continue if not lastBlank or (lastBlank and line): print '%s' % line if line: count += 1 lastBlank = False else: lastBlank = True if count == 20: break def main(): NNTPClient() DisplayFirst20() if __name__ == '__main__': main()