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时间:2010-04-03 来源:wgzlilu
#include "stdafx.h" int _tmain(int argc, _TCHAR* argv[]) { char k='a'; float j=2.0; int aa[3][3] = { {2},{4},{6}},i,*p = &aa[0][0]; k+=5/j; printf("%c",k); i=*p+1; for(i=0;i<2;i++) { if(i==0) { aa[i][i+1] = *p+1; } else { ++p; } printf("%d",*p); } printf("\n"); return 0; }
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