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时间:2009-07-15 来源:blackjimmy
def p(s): n9 = s.count("(") n0 = s.count(")") if n9 == n0: nn = s.rfind("(") left = s[0:nn+1] right = s[nn+1:] if left.count("(") == right.count(")"): print "yes" else: print "no" else: print "no" if __name__ == "__main__": str = "(((())))" p(str) str2 = "zx(4er(1(er(Yy)ol)ol)ik" p(str2) str3 = "zx(4er(1(er(Yy)o)l)ol)ik)" p(str3)
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