java网络编程－Ajax+servlet实例

时间：2007-10-17 来源：xiang588

Ajax异步请求,servlet产生随机数据,Html页面无刷新显示。
运行环境：jdk1.5+tomcat 5.5

一、ajaxServlet.java

package com;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.util.Random;
public class ajaxServlet extends HttpServlet{

private static final String CONTENT_TYPE="text/xml; charset=gb2312";
public void init() throws ServletException{}
public void doGet(HttpServletRequest request,HttpServletResponse response)
throws ServletException,IOException{
response.setContentType(CONTENT_TYPE);
response.setHeader("Cache-Control","no-cache");
response.setHeader("Pragma","no-cache");
response.setDateHeader("Expires",0);
PrintWriter out=response.getWriter();
String action=request.getParameter("action");
if(("send").equals(action)){
  Random random = new Random();
String AA=Integer.toString(Math.abs(random.nextInt()));
  String BB=Integer.toString(Math.abs(random.nextInt()));
String CC=Integer.toString(Math.abs(random.nextInt()));
  String DD=Integer.toString(Math.abs(random.nextInt()));
  StringBuffer sb=new StringBuffer();
  sb.append(AA);  sb.append("@@@");
  sb.append(BB);  sb.append("@@@");
  sb.append(CC);  sb.append("@@@");
  sb.append(DD);
  out.write(sb.toString());
  out.close();
  } }}

二、testajax.html
<html>
<head>
<title>AJAX.html</title>
</head>

<form>
<p>输入股票代码:
<input type="text" size="14" name="phone" id="phone"/>
</p>
<p>你交易的数量:</p>
<p><textarea name="order" rows="6" cols="50" id="order"></textarea></p>
<p><input type="submit" value="提交" id="submit" /></p>
</form>

</body>

　三、web.xml

<?xml version="1.0" encoding="ISO-8859-1"?>

<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
version="2.4">

<display-name>Welcome to Tomcat</display-name>
<description>
Welcome to Tomcat
</description>

<servlet>
<servlet-name>AajaxServlet</servlet-name>
<servlet-class>com.ajaxServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>AajaxServlet</servlet-name>
<url-pattern>/AajaxServlet</url-pattern>
</servlet-mapping>

</web-app>

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